47<= 8-7t

The solution to 47<= 8-7t is t<=-39/7

Solution

47 \leq 8 - 7 t

t \leq - \frac{39}{7}

Interval Notation

(- \infty, - \frac{39}{7}]

Decimal Notation

t \leq - 5.57142 \dots

Solution steps

47 \leq 8 - 7 t

Switch sides

8 - 7 t \geq 47

Move

8

to the right side

- 7 t \geq 39

Multiply both sides by

- 1

7 t \leq - 39

Divide both sides by

7

t \leq - \frac{39}{7}

1.5 \cdot 2

\frac{15 c}{12 ( d - 3 )} \cdot \frac{21 d}{6 c}

8 x^{3} - 64 y^{3}

30 n^{3} - 12 n^{2} - 18 n

(8 x^{4} y^{- 3}) (\frac{1}{2} x^{- 5} y^{2})