What are the solutions to the equation 3x^2-3x-5=0 ?

The solutions to the equation 3x^2-3x-5=0 are x=(3+sqrt(69))/6 ,x=(3-sqrt(69))/6

Find the zeros of 3x^2-3x-5=0

The zeros of 3x^2-3x-5=0 are x=(3+sqrt(69))/6 ,x=(3-sqrt(69))/6

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3 x^{2} - 3 x - 5 = 0

x = \frac{3 + 69}{6}, x = \frac{3 - 69}{6}

Solution steps

3 x^{2} - 3 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 3 ( - 5 )}{2 \cdot 3}

(- 3)^{2} - 4 \cdot 3 (- 5) = 69

x_{1, 2} = \frac{- ( - 3 ) \pm 69}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 69}{2 \cdot 3}, x_{2} = \frac{- ( - 3 ) - 69}{2 \cdot 3}

x = \frac{- ( - 3 ) + 69}{2 \cdot 3} : \frac{3 + 69}{6}

x = \frac{- ( - 3 ) - 69}{2 \cdot 3} : \frac{3 - 69}{6}

The solutions to the quadratic equation are:

x = \frac{3 + 69}{6}, x = \frac{3 - 69}{6}

88

\frac{1}{3 \cdot 0.00000005}

x (x + 2) = 5

4 x^{2} - 4 x + 1 \leq 0

- 2 (4 a - 3) = 4 (- a + 2)

What are the solutions to the equation 3x^2-3x-5=0 ?
The solutions to the equation 3x^2-3x-5=0 are x=(3+sqrt(69))/6 ,x=(3-sqrt(69))/6
Find the zeros of 3x^2-3x-5=0
The zeros of 3x^2-3x-5=0 are x=(3+sqrt(69))/6 ,x=(3-sqrt(69))/6