What is ((2a)/(t^2))^{-2} ?

The solution to ((2a)/(t^2))^{-2} is (t^4)/(4a^2)

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simplify ((2a)/(t^2))^{-2}

simplify

(\frac{2 a}{t ^{2}})^{- 2}

\frac{t ^{4}}{4 a ^{2}}

Solution steps

(\frac{2 a}{t ^{2}})^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(\frac{2 a}{t ^{2}})^{- 2} = \frac{1}{( \frac{2 a}{t ^{2}} ) ^{2}}

= \frac{1}{( \frac{2 a}{t ^{2}} ) ^{2}}

Simplify

(\frac{2 a}{t ^{2}})^{2} : \frac{4 a ^{2}}{t ^{4}}

= \frac{1}{\frac{4 a ^{2}}{t ^{4}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{t ^{4}}{4 a ^{2}}

9 n + 13 = 3 n + 62.2

\frac{2}{3} x^{2} - \frac{1}{2} x - \frac{3}{4} = 0

(\frac{5}{13})^{2}

\frac{( 5 + 6 i )}{( 6 - 5 i )}

4 u + 2 \geq 10