What are the solutions to the equation (4x-1)^2=43 ?

The solutions to the equation (4x-1)^2=43 are x=(sqrt(43)+1)/4 ,x=(-sqrt(43)+1)/4

Find the zeros of (4x-1)^2=43

The zeros of (4x-1)^2=43 are x=(sqrt(43)+1)/4 ,x=(-sqrt(43)+1)/4

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(4 x - 1)^{2} = 43

x = \frac{43 + 1}{4}, x = \frac{- 43 + 1}{4}

Solution steps

(4 x - 1)^{2} = 43

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x - 1 = 43 : x = \frac{43 + 1}{4}

Solve

4 x - 1 = - 43 : x = \frac{- 43 + 1}{4}

The solutions to the quadratic equation are:

x = \frac{43 + 1}{4}, x = \frac{- 43 + 1}{4}

\frac{( - 1 ) ^{2}}{2}

\frac{14 a ^{4} b ^{6} c ^{- 10}}{8 a ^{- 2} b ^{3} c ^{- 5}}

(x - 7)^{2} = 16

p^{2} + 7 pq - 18 q^{2}

7 x - 1 > 3 x + 7

What are the solutions to the equation (4x-1)^2=43 ?
The solutions to the equation (4x-1)^2=43 are x=(sqrt(43)+1)/4 ,x=(-sqrt(43)+1)/4
Find the zeros of (4x-1)^2=43
The zeros of (4x-1)^2=43 are x=(sqrt(43)+1)/4 ,x=(-sqrt(43)+1)/4