What are the solutions to the equation -16t^2+44t+28=0 ?

The solutions to the equation -16t^2+44t+28=0 are t=-(-11+sqrt(233))/8 ,t=(11+sqrt(233))/8

Find the zeros of -16t^2+44t+28=0

The zeros of -16t^2+44t+28=0 are t=-(-11+sqrt(233))/8 ,t=(11+sqrt(233))/8

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- 16 t^{2} + 44 t + 28 = 0

t = - \frac{- 11 + 233}{8}, t = \frac{11 + 233}{8}

Decimal Notation

t = - 0.53304 \dots, t = 3.28304 \dots

Solution steps

- 16 t^{2} + 44 t + 28 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 44 \pm 4 4 ^{2} - 4 ( - 16 ) \cdot 28}{2 ( - 16 )}

4 4^{2} - 4 (- 16) \cdot 28 = 4233

t_{1, 2} = \frac{- 44 \pm 4 233}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 44 + 4 233}{2 ( - 16 )}, t_{2} = \frac{- 44 - 4 233}{2 ( - 16 )}

t = \frac{- 44 + 4 233}{2 ( - 16 )} : - \frac{- 11 + 233}{8}

t = \frac{- 44 - 4 233}{2 ( - 16 )} : \frac{11 + 233}{8}

The solutions to the quadratic equation are:

t = - \frac{- 11 + 233}{8}, t = \frac{11 + 233}{8}

5 x - 6 = 2 x + 12

10 \geq j + 5

y - 7.55 = - 4.26

2 y - 1.7 = 3.3

\frac{1}{2} - 8

What are the solutions to the equation -16t^2+44t+28=0 ?
The solutions to the equation -16t^2+44t+28=0 are t=-(-11+sqrt(233))/8 ,t=(11+sqrt(233))/8
Find the zeros of -16t^2+44t+28=0
The zeros of -16t^2+44t+28=0 are t=-(-11+sqrt(233))/8 ,t=(11+sqrt(233))/8