What are the solutions to the equation 0=t^2-190t-6000 ?

The solutions to the equation 0=t^2-190t-6000 are t=5(19+sqrt(601)),t=5(19-sqrt(601))

Find the zeros of 0=t^2-190t-6000

The zeros of 0=t^2-190t-6000 are t=5(19+sqrt(601)),t=5(19-sqrt(601))

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0 = t^{2} - 190 t - 6000

t = 5 (19 + 601), t = 5 (19 - 601)

Solution steps

0 = t^{2} - 190 t - 6000

Switch sides

t^{2} - 190 t - 6000 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 190 ) \pm ( - 190 ) ^{2} - 4 \cdot 1 \cdot ( - 6000 )}{2 \cdot 1}

(- 190)^{2} - 4 \cdot 1 \cdot (- 6000) = 10601

t_{1, 2} = \frac{- ( - 190 ) \pm 10 601}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 190 ) + 10 601}{2 \cdot 1}, t_{2} = \frac{- ( - 190 ) - 10 601}{2 \cdot 1}

t = \frac{- ( - 190 ) + 10 601}{2 \cdot 1} : 5 (19 + 601)

t = \frac{- ( - 190 ) - 10 601}{2 \cdot 1} : 5 (19 - 601)

The solutions to the quadratic equation are:

t = 5 (19 + 601), t = 5 (19 - 601)

2 ∣ 6 - 2 x ∣ + 6 = 10

x^{\frac{1}{2}} \cdot x^{3}

20 t + \frac{1}{2} (9.8) t^{2} = 12 t + \frac{1}{2} (- 9.8) (t - 3)^{2}

40 = t^{2} + 3 t

x^{4} - 4 x^{3} - x^{2} + 4 x

What are the solutions to the equation 0=t^2-190t-6000 ?
The solutions to the equation 0=t^2-190t-6000 are t=5(19+sqrt(601)),t=5(19-sqrt(601))
Find the zeros of 0=t^2-190t-6000
The zeros of 0=t^2-190t-6000 are t=5(19+sqrt(601)),t=5(19-sqrt(601))