What are the solutions to the equation x^2+10x-96=0 ?

The solutions to the equation x^2+10x-96=0 are x=6,x=-16

Find the zeros of x^2+10x-96=0

The zeros of x^2+10x-96=0 are x=6,x=-16

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x^{2} + 10 x - 96 = 0

x = 6, x = - 16

Solution steps

x^{2} + 10 x - 96 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot ( - 96 )}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot (- 96) = 22

x_{1, 2} = \frac{- 10 \pm 22}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 22}{2 \cdot 1}, x_{2} = \frac{- 10 - 22}{2 \cdot 1}

x = \frac{- 10 + 22}{2 \cdot 1} : 6

x = \frac{- 10 - 22}{2 \cdot 1} : - 16

The solutions to the quadratic equation are:

x = 6, x = - 16

\frac{14}{2 2}

w^{2} = 64

\frac{- 1 + i}{- 5 i}

640 - 290 - 3160

8 x^{2} - 10 x - 7

What are the solutions to the equation x^2+10x-96=0 ?
The solutions to the equation x^2+10x-96=0 are x=6,x=-16
Find the zeros of x^2+10x-96=0
The zeros of x^2+10x-96=0 are x=6,x=-16