What are the solutions to the equation x^2-3x=0 ?

The solutions to the equation x^2-3x=0 are x=3,x=0

Find the zeros of x^2-3x=0

The zeros of x^2-3x=0 are x=3,x=0

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x^{2} - 3 x = 0

x = 3, x = 0

Solution steps

x^{2} - 3 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot 0 = 3

x_{1, 2} = \frac{- ( - 3 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 3}{2 \cdot 1}

x = \frac{- ( - 3 ) + 3}{2 \cdot 1} : 3

x = \frac{- ( - 3 ) - 3}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 3, x = 0

\frac{8}{4 + 4 i}

3 v - 14 < 43

2 x - 3 = x - 15

9 < 4 x + 1 < x + 16

3 x^{2} - 33 x - 6 = 0

What are the solutions to the equation x^2-3x=0 ?
The solutions to the equation x^2-3x=0 are x=3,x=0
Find the zeros of x^2-3x=0
The zeros of x^2-3x=0 are x=3,x=0