What are the solutions to the equation m^2-4m+7=0 ?

The solutions to the equation m^2-4m+7=0 are m=2+sqrt(3)i,m=2-sqrt(3)i

Find the zeros of m^2-4m+7=0

The zeros of m^2-4m+7=0 are m=2+sqrt(3)i,m=2-sqrt(3)i

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m^{2} - 4 m + 7 = 0

m = 2 + 3 i, m = 2 - 3 i

Solution steps

m^{2} - 4 m + 7 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot 7 : 23 i

m_{1, 2} = \frac{- ( - 4 ) \pm 2 3 i}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 4 ) + 2 3 i}{2 \cdot 1}, m_{2} = \frac{- ( - 4 ) - 2 3 i}{2 \cdot 1}

m = \frac{- ( - 4 ) + 2 3 i}{2 \cdot 1} : 2 + 3 i

m = \frac{- ( - 4 ) - 2 3 i}{2 \cdot 1} : 2 - 3 i

The solutions to the quadratic equation are:

m = 2 + 3 i, m = 2 - 3 i

6 k + 1 = 16 + 3 k

5 x^{2} + 28 x + 15

36 x^{2} - 21 = 0

2 x^{2} - 7 x + 3 > 0

u 1 + x^{2} + 1 - (ux)^{2}

What are the solutions to the equation m^2-4m+7=0 ?
The solutions to the equation m^2-4m+7=0 are m=2+sqrt(3)i,m=2-sqrt(3)i
Find the zeros of m^2-4m+7=0
The zeros of m^2-4m+7=0 are m=2+sqrt(3)i,m=2-sqrt(3)i