What are the solutions to the equation -4x^2-36=0 ?

The solutions to the equation -4x^2-36=0 are x=3i,x=-3i

Find the zeros of -4x^2-36=0

The zeros of -4x^2-36=0 are x=3i,x=-3i

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- 4 x^{2} - 36 = 0

x = 3 i, x = - 3 i

Solution steps

- 4 x^{2} - 36 = 0

Move

36

to the right side

- 4 x^{2} = 36

Divide both sides by

- 4

x^{2} = - 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 9, x = - - 9

- 9 = 3 i

- - 9 = - 3 i

x = 3 i, x = - 3 i

(- 3 (0) + 1) (0 - 5) > 0

2 x - 6 > 3 x - 11

390

- x^{2} + 18 x - 81 \leq 0

What are the solutions to the equation -4x^2-36=0 ?
The solutions to the equation -4x^2-36=0 are x=3i,x=-3i
Find the zeros of -4x^2-36=0
The zeros of -4x^2-36=0 are x=3i,x=-3i