What are the solutions to the equation v^2+v+5=0 ?

The solutions to the equation v^2+v+5=0 are v=-1/2+i(sqrt(19))/2 ,v=-1/2-i(sqrt(19))/2

Find the zeros of v^2+v+5=0

The zeros of v^2+v+5=0 are v=-1/2+i(sqrt(19))/2 ,v=-1/2-i(sqrt(19))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

v^{2} + v + 5 = 0

v = - \frac{1}{2} + i \frac{19}{2}, v = - \frac{1}{2} - i \frac{19}{2}

Solution steps

v^{2} + v + 5 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

Simplify

1^{2} - 4 \cdot 1 \cdot 5 : 19 i

v_{1, 2} = \frac{- 1 \pm 19 i}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- 1 + 19 i}{2 \cdot 1}, v_{2} = \frac{- 1 - 19 i}{2 \cdot 1}

v = \frac{- 1 + 19 i}{2 \cdot 1} : - \frac{1}{2} + i \frac{19}{2}

v = \frac{- 1 - 19 i}{2 \cdot 1} : - \frac{1}{2} - i \frac{19}{2}

The solutions to the quadratic equation are:

v = - \frac{1}{2} + i \frac{19}{2}, v = - \frac{1}{2} - i \frac{19}{2}

2 p^{2} - 4 p - 16 = 0

- 3 (- 5 x + 2) + x - 3 = 39

6 x + \frac{1}{12} - x - \frac{13}{9} = 5 x - \frac{3}{2} + \frac{x}{30}

\frac{3 - i}{2 + i}

8 x^{2} - 8 x + 2

What are the solutions to the equation v^2+v+5=0 ?
The solutions to the equation v^2+v+5=0 are v=-1/2+i(sqrt(19))/2 ,v=-1/2-i(sqrt(19))/2
Find the zeros of v^2+v+5=0
The zeros of v^2+v+5=0 are v=-1/2+i(sqrt(19))/2 ,v=-1/2-i(sqrt(19))/2