What are the solutions to the equation 6x^2-3x-2=0 ?

The solutions to the equation 6x^2-3x-2=0 are x=(3+sqrt(57))/(12),x=(3-sqrt(57))/(12)

Find the zeros of 6x^2-3x-2=0

The zeros of 6x^2-3x-2=0 are x=(3+sqrt(57))/(12),x=(3-sqrt(57))/(12)

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6 x^{2} - 3 x - 2 = 0

x = \frac{3 + 57}{12}, x = \frac{3 - 57}{12}

Solution steps

6 x^{2} - 3 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 6 ( - 2 )}{2 \cdot 6}

(- 3)^{2} - 4 \cdot 6 (- 2) = 57

x_{1, 2} = \frac{- ( - 3 ) \pm 57}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 57}{2 \cdot 6}, x_{2} = \frac{- ( - 3 ) - 57}{2 \cdot 6}

x = \frac{- ( - 3 ) + 57}{2 \cdot 6} : \frac{3 + 57}{12}

x = \frac{- ( - 3 ) - 57}{2 \cdot 6} : \frac{3 - 57}{12}

The solutions to the quadratic equation are:

x = \frac{3 + 57}{12}, x = \frac{3 - 57}{12}

(\frac{1}{4} x^{2})^{2}

x + \frac{3}{4} \leq \frac{1}{6}

11 x - 2 x + 15 = 8 + 7 + 9 x

x^{2} - 18 x + 70 = 0

c - 32 \geq 0

What are the solutions to the equation 6x^2-3x-2=0 ?
The solutions to the equation 6x^2-3x-2=0 are x=(3+sqrt(57))/(12),x=(3-sqrt(57))/(12)
Find the zeros of 6x^2-3x-2=0
The zeros of 6x^2-3x-2=0 are x=(3+sqrt(57))/(12),x=(3-sqrt(57))/(12)