What are the solutions to the equation 3x^2-12x+6=0 ?

The solutions to the equation 3x^2-12x+6=0 are x=2+sqrt(2),x=2-sqrt(2)

Find the zeros of 3x^2-12x+6=0

The zeros of 3x^2-12x+6=0 are x=2+sqrt(2),x=2-sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} - 12 x + 6 = 0

x = 2 + 2, x = 2 - 2

Decimal Notation

x = 3.41421 \dots, x = 0.58578 \dots

Solution steps

3 x^{2} - 12 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 3 \cdot 6}{2 \cdot 3}

(- 12)^{2} - 4 \cdot 3 \cdot 6 = 62

x_{1, 2} = \frac{- ( - 12 ) \pm 6 2}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 6 2}{2 \cdot 3}, x_{2} = \frac{- ( - 12 ) - 6 2}{2 \cdot 3}

x = \frac{- ( - 12 ) + 6 2}{2 \cdot 3} : 2 + 2

x = \frac{- ( - 12 ) - 6 2}{2 \cdot 3} : 2 - 2

The solutions to the quadratic equation are:

x = 2 + 2, x = 2 - 2

∣ x + 2 ∣ + ∣ x ∣ \leq 3

- 3 x - 5 < 10

6 x + 6 = 24

lo g_{e} (10)

98 x^{2} - 200 y^{2}

What are the solutions to the equation 3x^2-12x+6=0 ?
The solutions to the equation 3x^2-12x+6=0 are x=2+sqrt(2),x=2-sqrt(2)
Find the zeros of 3x^2-12x+6=0
The zeros of 3x^2-12x+6=0 are x=2+sqrt(2),x=2-sqrt(2)