What is (2x-3)(4x+5)<= (8x+1)(x-7) ?

The solution to (2x-3)(4x+5)<= (8x+1)(x-7) is x<= 8/53

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(2x-3)(4x+5)<= (8x+1)(x-7)

(2 x - 3) (4 x + 5) \leq (8 x + 1) (x - 7)

x \leq \frac{8}{53}

Interval Notation

(- \infty, \frac{8}{53}]

Decimal Notation

x \leq 0.15094 \dots

Solution steps

(2 x - 3) (4 x + 5) \leq (8 x + 1) (x - 7)

Rewrite in standard form

53 x - 8 \leq 0

Move

8

to the right side

53 x \leq 8

Divide both sides by

53

x \leq \frac{8}{53}

r - 14 = 23

10 - 2 x = 7 - 3 x

\frac{1}{2 x - 1} \leq x

- \frac{1}{5} + \frac{1}{2}

x^{3} + x^{2} - 16 x - 16

What is (2x-3)(4x+5)<= (8x+1)(x-7) ?
The solution to (2x-3)(4x+5)<= (8x+1)(x-7) is x<= 8/53