What are the solutions to the equation 2x^2-13x+4=0 ?

The solutions to the equation 2x^2-13x+4=0 are x=(13+sqrt(137))/4 ,x=(13-sqrt(137))/4

Find the zeros of 2x^2-13x+4=0

The zeros of 2x^2-13x+4=0 are x=(13+sqrt(137))/4 ,x=(13-sqrt(137))/4

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2 x^{2} - 13 x + 4 = 0

x = \frac{13 + 137}{4}, x = \frac{13 - 137}{4}

Solution steps

2 x^{2} - 13 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 2 \cdot 4}{2 \cdot 2}

(- 13)^{2} - 4 \cdot 2 \cdot 4 = 137

x_{1, 2} = \frac{- ( - 13 ) \pm 137}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 137}{2 \cdot 2}, x_{2} = \frac{- ( - 13 ) - 137}{2 \cdot 2}

x = \frac{- ( - 13 ) + 137}{2 \cdot 2} : \frac{13 + 137}{4}

x = \frac{- ( - 13 ) - 137}{2 \cdot 2} : \frac{13 - 137}{4}

The solutions to the quadratic equation are:

x = \frac{13 + 137}{4}, x = \frac{13 - 137}{4}

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e^{(0)}

3 x = 16

a^{6} + b^{3}

What are the solutions to the equation 2x^2-13x+4=0 ?
The solutions to the equation 2x^2-13x+4=0 are x=(13+sqrt(137))/4 ,x=(13-sqrt(137))/4
Find the zeros of 2x^2-13x+4=0
The zeros of 2x^2-13x+4=0 are x=(13+sqrt(137))/4 ,x=(13-sqrt(137))/4