What are the solutions to the equation 3(x^2-1)-2=-2 ?

The solutions to the equation 3(x^2-1)-2=-2 are x=1,x=-1

Find the zeros of 3(x^2-1)-2=-2

The zeros of 3(x^2-1)-2=-2 are x=1,x=-1

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3 (x^{2} - 1) - 2 = - 2

x = 1, x = - 1

Solution steps

3 (x^{2} - 1) - 2 = - 2

Move

2

to the right side

3 (x^{2} - 1) = 0

Divide both sides by

3

x^{2} - 1 = 0

Move

1

to the right side

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

(\frac{3}{2})^{\frac{3}{2}}

x^{2} - 8 x - 2 = 0

7252

\frac{1}{2} - 1

8 n + 6 - 2 n = 34

What are the solutions to the equation 3(x^2-1)-2=-2 ?
The solutions to the equation 3(x^2-1)-2=-2 are x=1,x=-1
Find the zeros of 3(x^2-1)-2=-2
The zeros of 3(x^2-1)-2=-2 are x=1,x=-1