What is log_{6}(12)+log_{6}(3) ?

The solution to log_{6}(12)+log_{6}(3) is 2

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simplify log_{6}(12)+log_{6}(3)

simplify

lo g_{6} (12) + lo g_{6} (3)

2

Solution steps

lo g_{6} (12) + lo g_{6} (3)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{6} (12) + lo g_{6} (3) = lo g_{6} (12 \cdot 3)

= lo g_{6} (12 \cdot 3)

Multiply the numbers:

12 \cdot 3 = 36

= lo g_{6} (36)

Factor the number:

36 = 6^{2}

= lo g_{6} (6^{2})

Apply log rule:

lo g_{a} (a^{b}) = b

= 2

96 - 163

\frac{1}{5} y + 11 = 3 - \frac{3}{5} y

a^{2} b^{2} c^{2} - a^{2} c^{2} x^{2} + a^{2} c^{2} y^{2}

\frac{8 ( - 6 ) - 5}{- 5 ( - 6 ) + 4}

x^{3} + x^{2} y^{5} + x y^{10} + y^{15}