What are the solutions to the equation 4p^2+25p+6=0 ?

The solutions to the equation 4p^2+25p+6=0 are p=-1/4 ,p=-6

Find the zeros of 4p^2+25p+6=0

The zeros of 4p^2+25p+6=0 are p=-1/4 ,p=-6

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4 p^{2} + 25 p + 6 = 0

p = - \frac{1}{4}, p = - 6

Decimal Notation

p = - 0.25, p = - 6

Solution steps

4 p^{2} + 25 p + 6 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 25 \pm 2 5 ^{2} - 4 \cdot 4 \cdot 6}{2 \cdot 4}

2 5^{2} - 4 \cdot 4 \cdot 6 = 23

p_{1, 2} = \frac{- 25 \pm 23}{2 \cdot 4}

Separate the solutions

p_{1} = \frac{- 25 + 23}{2 \cdot 4}, p_{2} = \frac{- 25 - 23}{2 \cdot 4}

p = \frac{- 25 + 23}{2 \cdot 4} : - \frac{1}{4}

p = \frac{- 25 - 23}{2 \cdot 4} : - 6

The solutions to the quadratic equation are:

p = - \frac{1}{4}, p = - 6

3 x - x + 7 = - 15

f = (\frac{1}{3})^{0}

- 3 \leq 2 - 5 x \leq 12

400 \cdot 0.05

x^{3} y - 9 x y

What are the solutions to the equation 4p^2+25p+6=0 ?
The solutions to the equation 4p^2+25p+6=0 are p=-1/4 ,p=-6
Find the zeros of 4p^2+25p+6=0
The zeros of 4p^2+25p+6=0 are p=-1/4 ,p=-6