What are the solutions to the equation x^2-4x+2=7 ?

The solutions to the equation x^2-4x+2=7 are x=5,x=-1

Find the zeros of x^2-4x+2=7

The zeros of x^2-4x+2=7 are x=5,x=-1

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x^{2} - 4 x + 2 = 7

x = 5, x = - 1

Solution steps

x^{2} - 4 x + 2 = 7

Move

7

to the left side

x^{2} - 4 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 5) = 6

x_{1, 2} = \frac{- ( - 4 ) \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 6}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 6}{2 \cdot 1}

x = \frac{- ( - 4 ) + 6}{2 \cdot 1} : 5

x = \frac{- ( - 4 ) - 6}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 5, x = - 1

\frac{1}{2} x - \frac{3}{5} < 2 - \frac{7}{10} x

0.3 \cdot 4

6 + 17 y = - 15 + 14 y

- x^{2} - x + 2

[1 + (\frac{1}{1000})] 1000

What are the solutions to the equation x^2-4x+2=7 ?
The solutions to the equation x^2-4x+2=7 are x=5,x=-1
Find the zeros of x^2-4x+2=7
The zeros of x^2-4x+2=7 are x=5,x=-1