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Popular >

2t^2+7t-4=0

Solution

2 t^{2} + 7 t - 4 = 0

Solution

t = \frac{1}{2}, t = - 4

+1

Solution steps

2 t^{2} + 7 t - 4 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 2 ( - 4 )}{2 \cdot 2}

7^{2} - 4 \cdot 2 (- 4) = 9

t_{1, 2} = \frac{- 7 \pm 9}{2 \cdot 2}

Separate the solutions

t_{1} = \frac{- 7 + 9}{2 \cdot 2}, t_{2} = \frac{- 7 - 9}{2 \cdot 2}

t = \frac{- 7 + 9}{2 \cdot 2} : \frac{1}{2}

t = \frac{- 7 - 9}{2 \cdot 2} : - 4

The solutions to the quadratic equation are:

t = \frac{1}{2}, t = - 4

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Frequently Asked Questions (FAQ)

What are the solutions to the equation 2t^2+7t-4=0 ?
The solutions to the equation 2t^2+7t-4=0 are t= 1/2 ,t=-4
Find the zeros of 2t^2+7t-4=0
The zeros of 2t^2+7t-4=0 are t= 1/2 ,t=-4