What is -x(x-5)(x+4)>0 ?

The solution to -x(x-5)(x+4)>0 is x<-4\lor 0<x<5

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-x(x-5)(x+4)>0

- x (x - 5) (x + 4) > 0

x < - 4 or 0 < x < 5

Interval Notation

(- \infty, - 4) \cup (0, 5)

Solution steps

- x (x - 5) (x + 4) > 0

Multiply both sides by

- 1

(reverse the inequality)

(- x (x - 5) (x + 4)) (- 1) < 0 \cdot (- 1)

Simplify

x (x - 5) (x + 4) < 0

Identify the intervals

x < - 4 or 0 < x < 5

b^{2} - b - 12

v^{2} - 8 v + 15 = 0

6 x = 2 x + 24

∣ x ∣ = x + 5

- \frac{2 x}{( x + 1 ) ^{2} ( x - 1 ) ^{2}} < 0