What are the solutions to the equation (3z-7)^2+25=0 ?

The solutions to the equation (3z-7)^2+25=0 are z= 7/3+i 5/3 ,z= 7/3-i 5/3

Find the zeros of (3z-7)^2+25=0

The zeros of (3z-7)^2+25=0 are z= 7/3+i 5/3 ,z= 7/3-i 5/3

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(3 z - 7)^{2} + 25 = 0

z = \frac{7}{3} + i \frac{5}{3}, z = \frac{7}{3} - i \frac{5}{3}

Solution steps

(3 z - 7)^{2} + 25 = 0

Move

25

to the right side

(3 z - 7)^{2} = - 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 z - 7 = - 25 : z = \frac{7}{3} + i \frac{5}{3}

Solve

3 z - 7 = - - 25 : z = \frac{7}{3} - i \frac{5}{3}

The solutions to the quadratic equation are:

z = \frac{7}{3} + i \frac{5}{3}, z = \frac{7}{3} - i \frac{5}{3}

T = 100 e^{- 0^{2} - 0^{2}}

x^{3} + 17 \leq 15

2 (3)

lo g_{4} (\frac{x y}{3})

6 x - 2 = x + 8

What are the solutions to the equation (3z-7)^2+25=0 ?
The solutions to the equation (3z-7)^2+25=0 are z= 7/3+i 5/3 ,z= 7/3-i 5/3
Find the zeros of (3z-7)^2+25=0
The zeros of (3z-7)^2+25=0 are z= 7/3+i 5/3 ,z= 7/3-i 5/3