What are the solutions to the equation 48x-16x^2=0 ?

The solutions to the equation 48x-16x^2=0 are x=0,x=3

Find the zeros of 48x-16x^2=0

The zeros of 48x-16x^2=0 are x=0,x=3

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48 x - 16 x^{2} = 0

x = 0, x = 3

Solution steps

48 x - 16 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 16 x^{2} + 48 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 48 \pm 4 8 ^{2} - 4 ( - 16 ) \cdot 0}{2 ( - 16 )}

4 8^{2} - 4 (- 16) \cdot 0 = 48

x_{1, 2} = \frac{- 48 \pm 48}{2 ( - 16 )}

Separate the solutions

x_{1} = \frac{- 48 + 48}{2 ( - 16 )}, x_{2} = \frac{- 48 - 48}{2 ( - 16 )}

x = \frac{- 48 + 48}{2 ( - 16 )} : 0

x = \frac{- 48 - 48}{2 ( - 16 )} : 3

The solutions to the quadratic equation are:

x = 0, x = 3

\frac{5}{5} - \frac{2}{5} x = 540 - \frac{3}{5} x - 86

5 + x < 1

x^{2} - 2 x - 1 \leq 0

- 125% + \frac{28}{20}

6 y^{2} + 13 y + 5

What are the solutions to the equation 48x-16x^2=0 ?
The solutions to the equation 48x-16x^2=0 are x=0,x=3
Find the zeros of 48x-16x^2=0
The zeros of 48x-16x^2=0 are x=0,x=3