What are the solutions to the equation 0=-x^2-8x-12 ?

The solutions to the equation 0=-x^2-8x-12 are x=-6,x=-2

Find the zeros of 0=-x^2-8x-12

The zeros of 0=-x^2-8x-12 are x=-6,x=-2

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0 = - x^{2} - 8 x - 12

x = - 6, x = - 2

Solution steps

0 = - x^{2} - 8 x - 12

Switch sides

- x^{2} - 8 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 ( - 1 ) ( - 12 )}{2 ( - 1 )}

(- 8)^{2} - 4 (- 1) (- 12) = 4

x_{1, 2} = \frac{- ( - 8 ) \pm 4}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4}{2 ( - 1 )}, x_{2} = \frac{- ( - 8 ) - 4}{2 ( - 1 )}

x = \frac{- ( - 8 ) + 4}{2 ( - 1 )} : - 6

x = \frac{- ( - 8 ) - 4}{2 ( - 1 )} : - 2

The solutions to the quadratic equation are:

x = - 6, x = - 2

48 = - 16 t^{2} + 32 t + 48

\frac{8 + 192}{4}

\frac{18}{x + 6} \leq 3

a c - a d + b c - b d

9 x = 7 x + 8

What are the solutions to the equation 0=-x^2-8x-12 ?
The solutions to the equation 0=-x^2-8x-12 are x=-6,x=-2
Find the zeros of 0=-x^2-8x-12
The zeros of 0=-x^2-8x-12 are x=-6,x=-2