What is (n^{3/5})/((n^-)^{3/4)} ?

The solution to (n^{3/5})/((n^-)^{3/4)} is n^{27/20}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (n^{3/5})/((n^-)^{3/4)}

simplify

\frac{n ^{\frac{3}{5}}}{( n ^{-} ) ^{\frac{3}{4}}}

n^{\frac{27}{20}}

Solution steps

\frac{n ^{\frac{3}{5}}}{( n ^{-} ) ^{\frac{3}{4}}}

(n^{-})^{\frac{3}{4}} = \frac{1}{n ^{\frac{3}{4}}}

= \frac{n ^{\frac{3}{5}}}{\frac{1}{n ^{\frac{3}{4}}}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{n ^{\frac{3}{5}} n ^{\frac{3}{4}}}{1}

Apply rule

\frac{a}{1} = a

= n^{\frac{3}{5}} n^{\frac{3}{4}}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

n^{\frac{3}{5}} n^{\frac{3}{4}} = n^{\frac{3}{5} + \frac{3}{4}}

= n^{\frac{3}{5} + \frac{3}{4}}

Join

\frac{3}{5} + \frac{3}{4} : \frac{27}{20}

= n^{\frac{27}{20}}

f + 13 = 22

x^{2} = 16

a = 2240 (1 + \frac{0.015}{18})^{18 \cdot 22.5}

5 x^{3} + 6 x^{2} - 45 x - 54

What is (n^{3/5})/((n^-)^{3/4)} ?
The solution to (n^{3/5})/((n^-)^{3/4)} is n^{27/20}