What is the answer to (x-2)(x+3)=(x+5)^2 ?

The answer to (x-2)(x+3)=(x+5)^2 is x=-31/9

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(x-2)(x+3)=(x+5)^2

(x - 2) (x + 3) = (x + 5)^{2}

x = - \frac{31}{9}

Decimal Notation

x = - 3.44444 \dots

Solution steps

(x - 2) (x + 3) = (x + 5)^{2}

Expand

(x - 2) (x + 3) : x^{2} + x - 6

Expand

(x + 5)^{2} : x^{2} + 10 x + 25

x^{2} + x - 6 = x^{2} + 10 x + 25

Move

6

to the right side

x^{2} + x = x^{2} + 10 x + 31

Subtract

x^{2} + 10 x

from both sides

x^{2} + x - (x^{2} + 10 x) = x^{2} + 10 x + 31 - (x^{2} + 10 x)

Simplify

- 9 x = 31

Divide both sides by

- 9

x = - \frac{31}{9}

\frac{- x}{y}

64 y^{3} - 27

\frac{11}{9 - 6}

6 u^{2} - 18 u = 0

∣ 2 x + 3 ∣ < x + 6

What is the answer to (x-2)(x+3)=(x+5)^2 ?
The answer to (x-2)(x+3)=(x+5)^2 is x=-31/9
Solve for x: (x-2)(x+3)=(x+5)^2
The solution is x=-31/9