What are the solutions to the equation x^2-4x-10=0 ?

The solutions to the equation x^2-4x-10=0 are x=2+sqrt(14),x=2-sqrt(14)

Find the zeros of x^2-4x-10=0

The zeros of x^2-4x-10=0 are x=2+sqrt(14),x=2-sqrt(14)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 4 x - 10 = 0

x = 2 + 14, x = 2 - 14

Decimal Notation

x = 5.74165 \dots, x = - 1.74165 \dots

Solution steps

x^{2} - 4 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 10) = 214

x_{1, 2} = \frac{- ( - 4 ) \pm 2 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 14}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 14}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 14}{2 \cdot 1} : 2 + 14

x = \frac{- ( - 4 ) - 2 14}{2 \cdot 1} : 2 - 14

The solutions to the quadratic equation are:

x = 2 + 14, x = 2 - 14

c - 3 = - 3

x + 1 = - x^{2} - 3 x + (4 x^{2} - 6)

- x + 22 - 4 x = - 63

\frac{( 6 x ^{2} y ^{3} ) ^{2}}{4 x ^{2} y ^{5}}

1000 = 800 (1 + \frac{r}{100})

What are the solutions to the equation x^2-4x-10=0 ?
The solutions to the equation x^2-4x-10=0 are x=2+sqrt(14),x=2-sqrt(14)
Find the zeros of x^2-4x-10=0
The zeros of x^2-4x-10=0 are x=2+sqrt(14),x=2-sqrt(14)