What are the solutions to the equation m^2-2m+5=0 ?

The solutions to the equation m^2-2m+5=0 are m=1+2i,m=1-2i

Find the zeros of m^2-2m+5=0

The zeros of m^2-2m+5=0 are m=1+2i,m=1-2i

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m^{2} - 2 m + 5 = 0

m = 1 + 2 i, m = 1 - 2 i

Solution steps

m^{2} - 2 m + 5 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 5 : 4 i

m_{1, 2} = \frac{- ( - 2 ) \pm 4 i}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 2 ) + 4 i}{2 \cdot 1}, m_{2} = \frac{- ( - 2 ) - 4 i}{2 \cdot 1}

m = \frac{- ( - 2 ) + 4 i}{2 \cdot 1} : 1 + 2 i

m = \frac{- ( - 2 ) - 4 i}{2 \cdot 1} : 1 - 2 i

The solutions to the quadratic equation are:

m = 1 + 2 i, m = 1 - 2 i

\frac{x}{2} = 3

t, G \cdot 5 = 1 t r

(\frac{3 x ^{\frac{1}{2}}}{10})^{2}

x^{2} + 24 x + 144 = 17

4 x^{2} - x = 0

What are the solutions to the equation m^2-2m+5=0 ?
The solutions to the equation m^2-2m+5=0 are m=1+2i,m=1-2i
Find the zeros of m^2-2m+5=0
The zeros of m^2-2m+5=0 are m=1+2i,m=1-2i