What are the solutions to the equation x^2+7x-7=0 ?

The solutions to the equation x^2+7x-7=0 are x=(-7+sqrt(77))/2 ,x=(-7-sqrt(77))/2

Find the zeros of x^2+7x-7=0

The zeros of x^2+7x-7=0 are x=(-7+sqrt(77))/2 ,x=(-7-sqrt(77))/2

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x^{2} + 7 x - 7 = 0

x = \frac{- 7 + 77}{2}, x = \frac{- 7 - 77}{2}

Decimal Notation

x = 0.88748 \dots, x = - 7.88748 \dots

Solution steps

x^{2} + 7 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 7) = 77

x_{1, 2} = \frac{- 7 \pm 77}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 77}{2 \cdot 1}, x_{2} = \frac{- 7 - 77}{2 \cdot 1}

x = \frac{- 7 + 77}{2 \cdot 1} : \frac{- 7 + 77}{2}

x = \frac{- 7 - 77}{2 \cdot 1} : \frac{- 7 - 77}{2}

The solutions to the quadratic equation are:

x = \frac{- 7 + 77}{2}, x = \frac{- 7 - 77}{2}

\frac{1}{4} a^{3} b - \frac{3}{5} a^{3} b + \frac{1}{6} a^{3} b

f = - (\frac{3}{2})^{5}

w^{2} - 10 w + 21

\frac{ln ( 2 )}{0.01}

- \frac{1}{3}

What are the solutions to the equation x^2+7x-7=0 ?
The solutions to the equation x^2+7x-7=0 are x=(-7+sqrt(77))/2 ,x=(-7-sqrt(77))/2
Find the zeros of x^2+7x-7=0
The zeros of x^2+7x-7=0 are x=(-7+sqrt(77))/2 ,x=(-7-sqrt(77))/2