What are the solutions to the equation 24=-16t^2+40t ?

The solutions to the equation 24=-16t^2+40t are t=1,t= 3/2

Find the zeros of 24=-16t^2+40t

The zeros of 24=-16t^2+40t are t=1,t= 3/2

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24 = - 16 t^{2} + 40 t

t = 1, t = \frac{3}{2}

Decimal Notation

t = 1, t = 1.5

Solution steps

24 = - 16 t^{2} + 40 t

Switch sides

- 16 t^{2} + 40 t = 24

Move

24

to the left side

- 16 t^{2} + 40 t - 24 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 ( - 16 ) ( - 24 )}{2 ( - 16 )}

4 0^{2} - 4 (- 16) (- 24) = 8

t_{1, 2} = \frac{- 40 \pm 8}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 40 + 8}{2 ( - 16 )}, t_{2} = \frac{- 40 - 8}{2 ( - 16 )}

t = \frac{- 40 + 8}{2 ( - 16 )} : 1

t = \frac{- 40 - 8}{2 ( - 16 )} : \frac{3}{2}

The solutions to the quadratic equation are:

t = 1, t = \frac{3}{2}

x (x - 3) \leq 10

∣ x + 3 ∣ = 14

4 a^{3} x - 4 a^{2} b + 3 bm - 3 am x

- 5 m^{2} - 65 = 0

2 x^{2} - 1 = 7 x

What are the solutions to the equation 24=-16t^2+40t ?
The solutions to the equation 24=-16t^2+40t are t=1,t= 3/2
Find the zeros of 24=-16t^2+40t
The zeros of 24=-16t^2+40t are t=1,t= 3/2