What are the solutions to the equation 8(2-x)^2=2(8-x)^2 ?

The solutions to the equation 8(2-x)^2=2(8-x)^2 are x=4,x=-4

Find the zeros of 8(2-x)^2=2(8-x)^2

The zeros of 8(2-x)^2=2(8-x)^2 are x=4,x=-4

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8 (2 - x)^{2} = 2 (8 - x)^{2}

x = 4, x = - 4

Solution steps

8 (2 - x)^{2} = 2 (8 - x)^{2}

Expand

8 (2 - x)^{2} : 32 - 32 x + 8 x^{2}

Expand

2 (8 - x)^{2} : 128 - 32 x + 2 x^{2}

32 - 32 x + 8 x^{2} = 128 - 32 x + 2 x^{2}

Move

32

to the right side

- 32 x + 8 x^{2} = 2 x^{2} - 32 x + 96

Move

32 x

to the left side

8 x^{2} = 2 x^{2} + 96

Move

2 x^{2}

to the left side

6 x^{2} = 96

Divide both sides by

6

x^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 16, x = - 16

16 = 4

- 16 = - 4

x = 4, x = - 4

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What are the solutions to the equation 8(2-x)^2=2(8-x)^2 ?
The solutions to the equation 8(2-x)^2=2(8-x)^2 are x=4,x=-4
Find the zeros of 8(2-x)^2=2(8-x)^2
The zeros of 8(2-x)^2=2(8-x)^2 are x=4,x=-4