What are the solutions to the equation x^2-12x=-36 ?

The solutions to the equation x^2-12x=-36 are x=6

Find the zeros of x^2-12x=-36

The zeros of x^2-12x=-36 are x=6

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x^{2} - 12 x = - 36

x = 6

Solution steps

x^{2} - 12 x = - 36

Move

36

to the left side

x^{2} - 12 x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 36}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 36 = 0

x_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 12 )}{2 \cdot 1}

\frac{- ( - 12 )}{2 \cdot 1} = 6

x = 6

The solution to the quadratic equation is:

x = 6

\frac{8 k}{9 k - 4} - \frac{3 k ^{3}}{2 k + 7}

- 4 w^{2} - 20 - 25 = 0

y^{2} = - 16

\frac{g}{2} + 1 \leq - 1

\frac{x - 2}{x + 1} \leq 1

What are the solutions to the equation x^2-12x=-36 ?
The solutions to the equation x^2-12x=-36 are x=6
Find the zeros of x^2-12x=-36
The zeros of x^2-12x=-36 are x=6