What is factor x^2+y^2+2xy ?

The solution to factor x^2+y^2+2xy is (x+y)^2

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factor x^2+y^2+2xy

factor

x^{2} + y^{2} + 2 x y

(x + y)^{2}

Solution steps

x^{2} + y^{2} + 2 x y

Group by common factors

= x^{2} + 2 x y + y^{2}

Apply Perfect Square Formula:

a^{2} + 2 ab + b^{2} = (a + b)^{2}

x^{2} + 2 x y + y^{2} = (x + y)^{2}

= (x + y)^{2}

- 14 \geq 7 n

\frac{10 !}{( 10 - 2 ) ! 2 !}

∣ w - 2 ∣ \leq 5

- 2 = \frac{x}{4} + 1

(\frac{1}{4})^{2} + 5 - [3 (\frac{1}{4} - \frac{2}{7}) + 1]