What are the solutions to the equation 0=x^2+8x+13 ?

The solutions to the equation 0=x^2+8x+13 are x=-4+sqrt(3),x=-4-sqrt(3)

Find the zeros of 0=x^2+8x+13

The zeros of 0=x^2+8x+13 are x=-4+sqrt(3),x=-4-sqrt(3)

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0 = x^{2} + 8 x + 13

x = - 4 + 3, x = - 4 - 3

Decimal Notation

x = - 2.26794 \dots, x = - 5.73205 \dots

Solution steps

0 = x^{2} + 8 x + 13

Switch sides

x^{2} + 8 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 13}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 13 = 23

x_{1, 2} = \frac{- 8 \pm 2 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 2 3}{2 \cdot 1}, x_{2} = \frac{- 8 - 2 3}{2 \cdot 1}

x = \frac{- 8 + 2 3}{2 \cdot 1} : - 4 + 3

x = \frac{- 8 - 2 3}{2 \cdot 1} : - 4 - 3

The solutions to the quadratic equation are:

x = - 4 + 3, x = - 4 - 3

\frac{16}{3} \cdot 2

23 x + 15 = 15 x - 9

7 x - 2 (5 - x) = 3 + 2 x + 8

\frac{1}{2} - \frac{1}{6}

3 a^{2} + 10 ab + 7 b^{2}

What are the solutions to the equation 0=x^2+8x+13 ?
The solutions to the equation 0=x^2+8x+13 are x=-4+sqrt(3),x=-4-sqrt(3)
Find the zeros of 0=x^2+8x+13
The zeros of 0=x^2+8x+13 are x=-4+sqrt(3),x=-4-sqrt(3)