What are the solutions to the equation 19x=-34-x^2 ?

The solutions to the equation 19x=-34-x^2 are x=-17,x=-2

Find the zeros of 19x=-34-x^2

The zeros of 19x=-34-x^2 are x=-17,x=-2

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19 x = - 34 - x^{2}

x = - 17, x = - 2

Solution steps

19 x = - 34 - x^{2}

Switch sides

- 34 - x^{2} = 19 x

Move

19 x

to the left side

- 34 - x^{2} - 19 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} - 19 x - 34 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 19 ) \pm ( - 19 ) ^{2} - 4 ( - 1 ) ( - 34 )}{2 ( - 1 )}

(- 19)^{2} - 4 (- 1) (- 34) = 15

x_{1, 2} = \frac{- ( - 19 ) \pm 15}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 19 ) + 15}{2 ( - 1 )}, x_{2} = \frac{- ( - 19 ) - 15}{2 ( - 1 )}

x = \frac{- ( - 19 ) + 15}{2 ( - 1 )} : - 17

x = \frac{- ( - 19 ) - 15}{2 ( - 1 )} : - 2

The solutions to the quadratic equation are:

x = - 17, x = - 2

0 \leq x^{2} - x - 2

3 x^{4} - 300 x^{2}

m^{2} - 9

(x + 11) (x + 5) = - 2

- 14 = - 9 x + 9

What are the solutions to the equation 19x=-34-x^2 ?
The solutions to the equation 19x=-34-x^2 are x=-17,x=-2
Find the zeros of 19x=-34-x^2
The zeros of 19x=-34-x^2 are x=-17,x=-2