What are the solutions to the equation s^2+8s=-15 ?

The solutions to the equation s^2+8s=-15 are s=-3,s=-5

Find the zeros of s^2+8s=-15

The zeros of s^2+8s=-15 are s=-3,s=-5

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s^{2} + 8 s = - 15

s = - 3, s = - 5

Solution steps

s^{2} + 8 s = - 15

Move

15

to the left side

s^{2} + 8 s + 15 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 15 = 2

s_{1, 2} = \frac{- 8 \pm 2}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 8 + 2}{2 \cdot 1}, s_{2} = \frac{- 8 - 2}{2 \cdot 1}

s = \frac{- 8 + 2}{2 \cdot 1} : - 3

s = \frac{- 8 - 2}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

s = - 3, s = - 5

2 (x + 1)^{2} = 8 - 3 x

\frac{x + 5}{x + 9} < 2

p - 19 \geq 47

∣ - 2 x + 5 ∣ - 4 > 3

6 x^{2} - 8 = 0

What are the solutions to the equation s^2+8s=-15 ?
The solutions to the equation s^2+8s=-15 are s=-3,s=-5
Find the zeros of s^2+8s=-15
The zeros of s^2+8s=-15 are s=-3,s=-5