What are the solutions to the equation (y+3)^2=-4(3-2) ?

The solutions to the equation (y+3)^2=-4(3-2) are y=2i-3,y=-2i-3

Find the zeros of (y+3)^2=-4(3-2)

The zeros of (y+3)^2=-4(3-2) are y=2i-3,y=-2i-3

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(y + 3)^{2} = - 4 (3 - 2)

y = 2 i - 3, y = - 2 i - 3

Solution steps

(y + 3)^{2} = - 4 (3 - 2)

Simplify

- 4 (3 - 2) : - 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

y + 3 = - 4 : y = 2 i - 3

Solve

y + 3 = - - 4 : y = - 2 i - 3

The solutions to the quadratic equation are:

y = 2 i - 3, y = - 2 i - 3

7^{- 2} \cdot 7^{- 6}

x^{3} z^{3} - 3 x^{2} z^{2} y + 3 x z y^{2} - z^{3}

2 = 3 n - 5 n

- 9 + 8

4 \geq \frac{s}{- 2}

What are the solutions to the equation (y+3)^2=-4(3-2) ?
The solutions to the equation (y+3)^2=-4(3-2) are y=2i-3,y=-2i-3
Find the zeros of (y+3)^2=-4(3-2)
The zeros of (y+3)^2=-4(3-2) are y=2i-3,y=-2i-3