What are the solutions to the equation 3x^2-30x+72=0 ?

The solutions to the equation 3x^2-30x+72=0 are x=6,x=4

Find the zeros of 3x^2-30x+72=0

The zeros of 3x^2-30x+72=0 are x=6,x=4

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3 x^{2} - 30 x + 72 = 0

x = 6, x = 4

Solution steps

3 x^{2} - 30 x + 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 30 ) \pm ( - 30 ) ^{2} - 4 \cdot 3 \cdot 72}{2 \cdot 3}

(- 30)^{2} - 4 \cdot 3 \cdot 72 = 6

x_{1, 2} = \frac{- ( - 30 ) \pm 6}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 30 ) + 6}{2 \cdot 3}, x_{2} = \frac{- ( - 30 ) - 6}{2 \cdot 3}

x = \frac{- ( - 30 ) + 6}{2 \cdot 3} : 6

x = \frac{- ( - 30 ) - 6}{2 \cdot 3} : 4

The solutions to the quadratic equation are:

x = 6, x = 4

4 y^{2} + 11 y - 3 = 0

4 (x + 3) = 3 x + 2 + x

\frac{1}{e ^{- 1}}

\frac{8 a ^{3} - b ^{3}}{4 a ^{2} - b ^{2}}

\frac{3}{4} x^{2} - 5 = 16

What are the solutions to the equation 3x^2-30x+72=0 ?
The solutions to the equation 3x^2-30x+72=0 are x=6,x=4
Find the zeros of 3x^2-30x+72=0
The zeros of 3x^2-30x+72=0 are x=6,x=4