What is x+1<= 6\land 1/3 x<-2 ?

The solution to x+1<= 6\land 1/3 x<-2 is x<-6

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x+1<= 6\land 1/3 x<-2

x + 1 \leq 6 and \frac{1}{3} x < - 2

x < - 6

Interval Notation

(- \infty, - 6)

Solution steps

x + 1 \leq 6 and \frac{1}{3} x < - 2

x + 1 \leq 6 : x \leq 5

\frac{1}{3} x < - 2 : x < - 6

Combine the intervals

x \leq 5 and x < - 6

Merge Overlapping Intervals

x < - 6

x^{2} + 10 x + 17 = 0

lo g_{3} (4) = 81

4 x^{2} + 8 x

i^{7}

a (- \frac{b}{2 a})^{2} + b (- \frac{b}{2 a}) + c