What are the solutions to the equation 15x^2-x-6=0 ?

The solutions to the equation 15x^2-x-6=0 are x= 2/3 ,x=-3/5

Find the zeros of 15x^2-x-6=0

The zeros of 15x^2-x-6=0 are x= 2/3 ,x=-3/5

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15 x^{2} - x - 6 = 0

x = \frac{2}{3}, x = - \frac{3}{5}

Solution steps

15 x^{2} - x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 15 ( - 6 )}{2 \cdot 15}

(- 1)^{2} - 4 \cdot 15 (- 6) = 19

x_{1, 2} = \frac{- ( - 1 ) \pm 19}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 19}{2 \cdot 15}, x_{2} = \frac{- ( - 1 ) - 19}{2 \cdot 15}

x = \frac{- ( - 1 ) + 19}{2 \cdot 15} : \frac{2}{3}

x = \frac{- ( - 1 ) - 19}{2 \cdot 15} : - \frac{3}{5}

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - \frac{3}{5}

- 3 (3 x + 15) - (10 + x) = 35

x^{2} - 1 = x^{2} - 1

7 t - 6 v^{2} + t v - 42 v

16 m^{2} - 40 mn + 25 n^{2}

\frac{\frac{40}{41}}{\frac{9}{41}}

What are the solutions to the equation 15x^2-x-6=0 ?
The solutions to the equation 15x^2-x-6=0 are x= 2/3 ,x=-3/5
Find the zeros of 15x^2-x-6=0
The zeros of 15x^2-x-6=0 are x= 2/3 ,x=-3/5