What are the solutions to the equation 2x^2+9x+7=3 ?

The solutions to the equation 2x^2+9x+7=3 are x=-1/2 ,x=-4

Find the zeros of 2x^2+9x+7=3

The zeros of 2x^2+9x+7=3 are x=-1/2 ,x=-4

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2 x^{2} + 9 x + 7 = 3

x = - \frac{1}{2}, x = - 4

Decimal Notation

x = - 0.5, x = - 4

Solution steps

2 x^{2} + 9 x + 7 = 3

Move

3

to the left side

2 x^{2} + 9 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 2 \cdot 4}{2 \cdot 2}

9^{2} - 4 \cdot 2 \cdot 4 = 7

x_{1, 2} = \frac{- 9 \pm 7}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 9 + 7}{2 \cdot 2}, x_{2} = \frac{- 9 - 7}{2 \cdot 2}

x = \frac{- 9 + 7}{2 \cdot 2} : - \frac{1}{2}

x = \frac{- 9 - 7}{2 \cdot 2} : - 4

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = - 4

- 21 x^{4} y^{2} z^{3} - 6 x^{8} y^{4} z^{5}

- 4 (x - 2) = 64

20 - 2 p > - 2 (p + 2) + 4 p

(\frac{11400}{5700})^{\frac{1}{16}} - 1

3 x + 10 < 34

What are the solutions to the equation 2x^2+9x+7=3 ?
The solutions to the equation 2x^2+9x+7=3 are x=-1/2 ,x=-4
Find the zeros of 2x^2+9x+7=3
The zeros of 2x^2+9x+7=3 are x=-1/2 ,x=-4