What are the solutions to the equation (x+3)^2-4=0 ?

The solutions to the equation (x+3)^2-4=0 are x=-1,x=-5

Find the zeros of (x+3)^2-4=0

The zeros of (x+3)^2-4=0 are x=-1,x=-5

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(x + 3)^{2} - 4 = 0

x = - 1, x = - 5

Solution steps

(x + 3)^{2} - 4 = 0

Move

4

to the right side

(x + 3)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = 4 : x = - 1

Solve

x + 3 = - 4 : x = - 5

The solutions to the quadratic equation are:

x = - 1, x = - 5

25 x^{2} - 5 x - 20

- 2 a (a + b - 5) + 3 (- 5 a + 2 b) + b (6 a + b - 8)

40 + 4.5 x = 112

\frac{8 3}{3}

∣ 2 x + 3 ∣ \geq 8

What are the solutions to the equation (x+3)^2-4=0 ?
The solutions to the equation (x+3)^2-4=0 are x=-1,x=-5
Find the zeros of (x+3)^2-4=0
The zeros of (x+3)^2-4=0 are x=-1,x=-5