What are the solutions to the equation a^2+a+a^2=28 ?

The solutions to the equation a^2+a+a^2=28 are a= 7/2 ,a=-4

Find the zeros of a^2+a+a^2=28

The zeros of a^2+a+a^2=28 are a= 7/2 ,a=-4

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a^{2} + a + a^{2} = 28

a = \frac{7}{2}, a = - 4

Decimal Notation

a = 3.5, a = - 4

Solution steps

a^{2} + a + a^{2} = 28

Refine

2 a^{2} + a = 28

Move

28

to the left side

2 a^{2} + a - 28 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 ( - 28 )}{2 \cdot 2}

1^{2} - 4 \cdot 2 (- 28) = 15

a_{1, 2} = \frac{- 1 \pm 15}{2 \cdot 2}

Separate the solutions

a_{1} = \frac{- 1 + 15}{2 \cdot 2}, a_{2} = \frac{- 1 - 15}{2 \cdot 2}

a = \frac{- 1 + 15}{2 \cdot 2} : \frac{7}{2}

a = \frac{- 1 - 15}{2 \cdot 2} : - 4

The solutions to the quadratic equation are:

a = \frac{7}{2}, a = - 4

16 + 9

3 t^{2} - 30 t + 72

- 5 - 3 m - m < 7 m - 5

- 3 - 3 x = 33

(\frac{1}{4})^{\frac{1}{2}}

What are the solutions to the equation a^2+a+a^2=28 ?
The solutions to the equation a^2+a+a^2=28 are a= 7/2 ,a=-4
Find the zeros of a^2+a+a^2=28
The zeros of a^2+a+a^2=28 are a= 7/2 ,a=-4