What are the solutions to the equation w^2-w-6=0 ?

The solutions to the equation w^2-w-6=0 are w=3,w=-2

Find the zeros of w^2-w-6=0

The zeros of w^2-w-6=0 are w=3,w=-2

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w^{2} - w - 6 = 0

w = 3, w = - 2

Solution steps

w^{2} - w - 6 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 6) = 5

w_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- ( - 1 ) + 5}{2 \cdot 1}, w_{2} = \frac{- ( - 1 ) - 5}{2 \cdot 1}

w = \frac{- ( - 1 ) + 5}{2 \cdot 1} : 3

w = \frac{- ( - 1 ) - 5}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

w = 3, w = - 2

(a^{- 2} + b^{- 2})^{- 1}

2 x^{2} = 10 x

5^{4} \cdot 5^{3}

a \frac{4}{7}

\frac{1225 π}{8} \cdot \frac{1024}{3}

What are the solutions to the equation w^2-w-6=0 ?
The solutions to the equation w^2-w-6=0 are w=3,w=-2
Find the zeros of w^2-w-6=0
The zeros of w^2-w-6=0 are w=3,w=-2