What are the solutions to the equation x^2-10x+23=0 ?

The solutions to the equation x^2-10x+23=0 are x=5+sqrt(2),x=5-sqrt(2)

Find the zeros of x^2-10x+23=0

The zeros of x^2-10x+23=0 are x=5+sqrt(2),x=5-sqrt(2)

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x^{2} - 10 x + 23 = 0

x = 5 + 2, x = 5 - 2

Decimal

x = 6.41421 \dots, x = 3.58578 \dots

Solution steps

x^{2} - 10 x + 23 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 23}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 23 = 22

x_{1, 2} = \frac{- ( - 10 ) \pm 2 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 2}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 2 2}{2 \cdot 1}

x = \frac{- ( - 10 ) + 2 2}{2 \cdot 1} : 5 + 2

x = \frac{- ( - 10 ) - 2 2}{2 \cdot 1} : 5 - 2

The solutions to the quadratic equation are:

x = 5 + 2, x = 5 - 2

16 - 83 + 3

125 m^{3} + 27

n^{2} + 6 n - 40

x^{3} + x^{2} + 3 x - 5

∣ 3 x - 2 ∣ > 10

What are the solutions to the equation x^2-10x+23=0 ?
The solutions to the equation x^2-10x+23=0 are x=5+sqrt(2),x=5-sqrt(2)
Find the zeros of x^2-10x+23=0
The zeros of x^2-10x+23=0 are x=5+sqrt(2),x=5-sqrt(2)