What are the solutions to the equation (x-10)^2-48=0 ?

The solutions to the equation (x-10)^2-48=0 are x=4sqrt(3)+10,x=-4sqrt(3)+10

Find the zeros of (x-10)^2-48=0

The zeros of (x-10)^2-48=0 are x=4sqrt(3)+10,x=-4sqrt(3)+10

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(x - 10)^{2} - 48 = 0

x = 43 + 10, x = - 43 + 10

Decimal Notation

x = 16.92820 \dots, x = 3.07179 \dots

Solution steps

(x - 10)^{2} - 48 = 0

Move

48

to the right side

(x - 10)^{2} = 48

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 10 = 48 : x = 43 + 10

Solve

x - 10 = - 48 : x = - 43 + 10

The solutions to the quadratic equation are:

x = 43 + 10, x = - 43 + 10

\frac{\frac{1}{2}}{1}

2 6^{2}

7 - 5 + 3 x - 1 = 3 x + 1

\frac{10 x + 5 z}{14 x ^{2} + 5 x z - z ^{2}}

2 s^{2} + 17 s + 8

What are the solutions to the equation (x-10)^2-48=0 ?
The solutions to the equation (x-10)^2-48=0 are x=4sqrt(3)+10,x=-4sqrt(3)+10
Find the zeros of (x-10)^2-48=0
The zeros of (x-10)^2-48=0 are x=4sqrt(3)+10,x=-4sqrt(3)+10