What are the solutions to the equation 60=8x^2+157x ?

The solutions to the equation 60=8x^2+157x are x= 3/8 ,x=-20

Find the zeros of 60=8x^2+157x

The zeros of 60=8x^2+157x are x= 3/8 ,x=-20

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

60 = 8 x^{2} + 157 x

x = \frac{3}{8}, x = - 20

Decimal Notation

x = 0.375, x = - 20

Solution steps

60 = 8 x^{2} + 157 x

Switch sides

8 x^{2} + 157 x = 60

Move

60

to the left side

8 x^{2} + 157 x - 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 157 \pm 15 7 ^{2} - 4 \cdot 8 ( - 60 )}{2 \cdot 8}

15 7^{2} - 4 \cdot 8 (- 60) = 163

x_{1, 2} = \frac{- 157 \pm 163}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 157 + 163}{2 \cdot 8}, x_{2} = \frac{- 157 - 163}{2 \cdot 8}

x = \frac{- 157 + 163}{2 \cdot 8} : \frac{3}{8}

x = \frac{- 157 - 163}{2 \cdot 8} : - 20

The solutions to the quadratic equation are:

x = \frac{3}{8}, x = - 20

\frac{r}{5} - 6 = - 1

- 3 x = x - (6 - 2 x)

2 \leq x - 2 \leq 7

4 x^{2} - 17 x + 4

2 (h - 8) - h = h - 16

What are the solutions to the equation 60=8x^2+157x ?
The solutions to the equation 60=8x^2+157x are x= 3/8 ,x=-20
Find the zeros of 60=8x^2+157x
The zeros of 60=8x^2+157x are x= 3/8 ,x=-20