What is (x+5)(x-2)(x-1)(x+1)<0 ?

The solution to (x+5)(x-2)(x-1)(x+1)<0 is -5<x<-1\lor 1<x<2

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(x+5)(x-2)(x-1)(x+1)<0

(x + 5) (x - 2) (x - 1) (x + 1) < 0

- 5 < x < - 1 or 1 < x < 2

Interval Notation

(- 5, - 1) \cup (1, 2)

Solution steps

(x + 5) (x - 2) (x - 1) (x + 1) < 0

Identify the intervals

- 5 < x < - 1 or 1 < x < 2

(1 8^{2})^{\frac{1}{3}}

6 x + x (x - 13) = 18

63 n^{2} + 150 n + 75

3 ∣ 2 y + 3 ∣ > 12

16 a^{2} - 24 ab + 9 b^{2}

What is (x+5)(x-2)(x-1)(x+1)<0 ?
The solution to (x+5)(x-2)(x-1)(x+1)<0 is -5<x<-1\lor 1<x<2