What are the solutions to the equation x^{(2)}-25=0 ?

The solutions to the equation x^{(2)}-25=0 are x=5,x=-5

Find the zeros of x^{(2)}-25=0

The zeros of x^{(2)}-25=0 are x=5,x=-5

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x^{(2)} - 25 = 0

x = 5, x = - 5

Solution steps

x^{(2)} - 25 = 0

Refine

x^{2} - 25 = 0

Move

25

to the right side

x^{2} = 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 25, x = - 25

25 = 5

- 25 = - 5

x = 5, x = - 5

- 3 (x + 5) > 3

\frac{20 !}{14 ! \cdot 6 !}

43 \cdot 2

16 x^{2} c + 8 x y d - 16 x^{2} d - 8 x yc

2 x - 68 = 3 x

What are the solutions to the equation x^{(2)}-25=0 ?
The solutions to the equation x^{(2)}-25=0 are x=5,x=-5
Find the zeros of x^{(2)}-25=0
The zeros of x^{(2)}-25=0 are x=5,x=-5