What are the solutions to the equation -3x^2-27x=42 ?

The solutions to the equation -3x^2-27x=42 are x=-7,x=-2

Find the zeros of -3x^2-27x=42

The zeros of -3x^2-27x=42 are x=-7,x=-2

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- 3 x^{2} - 27 x = 42

x = - 7, x = - 2

Solution steps

- 3 x^{2} - 27 x = 42

Move

42

to the left side

- 3 x^{2} - 27 x - 42 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 27 ) \pm ( - 27 ) ^{2} - 4 ( - 3 ) ( - 42 )}{2 ( - 3 )}

(- 27)^{2} - 4 (- 3) (- 42) = 15

x_{1, 2} = \frac{- ( - 27 ) \pm 15}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 27 ) + 15}{2 ( - 3 )}, x_{2} = \frac{- ( - 27 ) - 15}{2 ( - 3 )}

x = \frac{- ( - 27 ) + 15}{2 ( - 3 )} : - 7

x = \frac{- ( - 27 ) - 15}{2 ( - 3 )} : - 2

The solutions to the quadratic equation are:

x = - 7, x = - 2

\frac{20 \cdot ( 49.24 + 8.68 j )}{( 20 + 40 j )}

\frac{6}{5} + \frac{x}{5}

x + 6 = 3 x - 2

16 t^{2} - 4 t + 3 = 0

n - \frac{11}{12} \geq - \frac{5}{18}

What are the solutions to the equation -3x^2-27x=42 ?
The solutions to the equation -3x^2-27x=42 are x=-7,x=-2
Find the zeros of -3x^2-27x=42
The zeros of -3x^2-27x=42 are x=-7,x=-2